Convert Windows TCHAR argv list to classical char * argv

By , October 21, 2010

Many people used to classical C have hard time adopting the code to Windows types. The code below illustrates one of the frequent questions: how to use TCHAR arguments with good old code expecting char * in arguments with minimum blood?

#include "stdafx.h"
#include "stdio.h"
#include "stdlib.h"


// returns number of TCHARs in string
int wstrlen(_TCHAR * wstr)
{
    int l_idx = 0;
    while (((char*)wstr)[l_idx]!=0) l_idx+=2;
    return l_idx;
}

 
// Allocate char string and copy TCHAR->char->string
char * wstrdup(_TCHAR * wSrc)
{
    int l_idx=0;
    int l_len = wstrlen(wSrc);
    char * l_nstr = (char*)malloc(l_len);
    if (l_nstr) {
        do {
           l_nstr[l_idx] = (char)wSrc[l_idx];
           l_idx++;
        } while ((char)wSrc[l_idx]!=0);
    }
    nstr[l_idx] = 0;
    return l_nstr;
}

 

// allocate argn structure parallel to argv
// argn must be released
char ** allocate_argn (int argc, _TCHAR* argv[])
{
    char ** l_argn = (char **)malloc(argc * sizeof(char*));
    for (int idx=0; idx<argc; idx++) {
        l_argn[idx] = wstrdup(argv[idx]);
    }
    return l_argn;
}

// release argn and its content
void release_argn(int argc, char ** nargv)
{
    for (int idx=0; idx<argc; idx++) {
        free(nargv[idx]);
    }
    free(nargv);
}

 
////////////////////////////////////////////////////////////////////////
//////////////////////////////////////////////////////////////////////// 
// Use exampe:
////////////////////////////////////////////////////////////////////////

int _tmain(int argc, _TCHAR* argv[])
{
    char ** argn = allocate_argn(argc, argv);
    // Optionally #define argv argn
    if (argc>1) {
            printf(“Arg 1 = ‘%s’\n”, argn[1]); // Just argn intead of argv
    }
    release_argn(argc, argn);
    return 0;
}

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